Answers to UNIT 6 Self Test:
1. (a) Since this compound is on the left side of the arrow it is a reactant.
2. (c) decomposition since single reactant breaks down into two products
3. (a)
4. (a) CaI2 because Ca is +2 and I is -1.
5. (a) metal must be above metal ion on the activity series for a reaction to occur.
6. (d) Ag is lowest on the activity series therefore its ion would be replaced by all the others.
7. (a) since Ca is higher than Cu on the activity series
8. (d) both (c) and (b) are correct interpretations of a balanced chemical equation
9. (d) 2.5 mol *[2 mol/1mol] = 5.0 mol
10. (c) 1 mol *[8 mol/2 mol] = 4 mol
11. (c) 13 L *[2 L/1 L] = 26 L
12. (a) Since 2.0 mol Zn requires only 4.0 mol HCl
Part 2 Problems (see board in class for work)
a. Zn + 2 HCl à H2(g) + ZnCl2 single replacement
b. 3AgNO3 + AlI3 à 3AgI(s) + Al(NO3)3 double replacement
c. 2 Al2O3 à 4 Al + 3 O2(g) decomposition
d. 2 C4H10 + 13 O2 à 8 CO2(g) + 10 H2O(g) combustion
e. 2 Fe + 3 Br2 à 2 FeBr3 direct combination
f. Na2SO3 + H2SO4 à Na2SO4 + H2O + SO2(g) double replacement (and decomposition)
2 Li3PO4 + 3 Zn(NO3)2 à 6 LiNO3(aq) + Zn3(PO4)2 (s) one of the precipitate
(a) FeCl3(aq) + 3 NaOH(aq) à Fe(OH)3(s) + 3 NaCl(aq)
(b) 2 HCl(aq) + CaCO3(aq) à CaCl2(aq) + H2O(l) + CO2(g)
(c) Al2O3(s) + 3 H2O(l) à 2 Al(OH)3(s)
(a) 2 C6H14(g) + 19 O2(g) à 12 CO2 + 14 H2O
(b) 2 NCl3(s) à N2 + 3 H2
(c) 3 Zn(s) +
2 FeCl3(aq)
à
3 ZnCl2 + 2 Fe
(reaction does occur)
5. (a) 12.2 L (b) 75.0 g 6. 2.06 x 1023 molecules 7. 378 g Al2O3 8. Aluminum