
Answers to Second Semester Exam Review Lab-Based Problems
Chemistry May 2007
Unit 7: States of Matter “Getting the Volume Right”
Task 1: Determine how much HCl and sodium carbonate she should use to produce 1.00 L of gas. Clearly lay out the chemical equations and calculations. Explain with a sentence or two what a set of calculations are determining.
Based on the stoichiometry and assuming 100 mL of HCl solution in which 88 mL of my CO2 will dissolve, I will need 5.04 g of sodium carbonate and 95.2 mL of 1 M HCl. This was determined by using 1.08 L in the ideal gas law equation in order to determine the moles of CO2 I need to yield the 1.00 L volume I am aiming for. In the actual experiment I will use a slight excess of the HCl. I will use 110 mL in order to ensure that all the sodium carbonate reacts.
Task 2: Simply and clearly describe the procedural steps that the student needs to take to accomplish this task in the lab. Point out any particular pitfalls that she should avoid.
[I leave the answer of this to you the student.]
Unit 6: Stoichiometry – Determining the formula of a New Salt
A student is analyzing a hydrated salt, containing Cr, Cl and H2O. She must determine the empirical formula of the salt including the moles of water to salt ratio. To do so she gets a clean, dry, crucible and weighs it. She then puts about two grams of the salt into the crucible, weighs it again. She meticulously heats the salt noting a complete change in color as the heating progresses. After she is satisfied that she has thoroughly dehydrated the salt, she lets the crucible cool and weighs it. She then dissolves the salt in a small amount of water and adds a large piece of Aluminum wire. She allows the wire to completely react and notes that a new metal has formed on the bottom of the beaker and the aluminum wire has shrunk significantly. She separates the new metal and filters it. She rinses and allows the filtered metal to dry. She records the following data during the course of the lab:
Mass of empty crucible: 12.96 g
Mass of crucible and hydrated salt: 14.97 g
Mass of crucible and salt after heating: 14.60 g
Mass of filter paper: 1.27 g
Mass of filter paper and metal: 1.81 g
Clearly and thoroughly lay out all calculations and steps for your solution to finding the empirical formula.
Mass of water = 14.97 g - 14.60 g = 0.37 g
Mass of Cr metal = 1.81 g - 1.27 g = 0.54 g
mass of chlorine = [14.60 g - 12.96 g] - 0.54 g = 1.10 g
moles of water = 0.37 g / 18 g = 0.021 mol H2O
moles of Cr = 0.54 g / 52 g = 0.010 mol Cr
moles of Cl = 1.10 g / 35.45 g = 0.031 mole Cl
mole ratio 0.031 Cl / 0.010 mol Cr = 3 Cl : 1 Cr
mole ratio 0.021 H2O / 0.010 mol Cr = 2 H2O : 1 Cr
Empirical Formula: CrCl3 - 2H2O
Answer the following questions.
Al + CrCl3 --> AlCl3 + Cr
2. What effect on the final complete empirical formula would not driving off all the water have had? If all the water is not driven off this will make the mole of H2O too small and the moles of Cl too large.
Unit 10: Acids and Bases: Turn it Pink! Acid Solution Stoichiometry
Questions: